4x^2+300x-175=0

Solution for 4x^2+300x-175=0 equation:

4x^2+300x-175=0

a = 4; b = 300; c = -175;
Δ = b2-4ac
Δ = 3002-4·4·(-175)
Δ = 92800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{92800}=\sqrt{1600*58}=\sqrt{1600}*\sqrt{58}=40\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-40\sqrt{58}}{2*4}=\frac{-300-40\sqrt{58}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+40\sqrt{58}}{2*4}=\frac{-300+40\sqrt{58}}{8}
$